Collection element set in Spring

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With this example we will show you how to inject Collections in Spring Bean set.

In order to show how Collections can be injected in a Spring Bean we will create a simple Spring Bean with a property Set.

If you already have an idea on how to create a maven project in Eclipse will be great otherwise I will tell you here how to create a maven project in Eclipse.
Prerequisites

The following things are required in order to run the application

Eclipse Kepler
JDK 1.8
Have maven 3 installed and configured
Spring dependencies in pom.xml

Now we will see the below steps how to create a maven based spring project in Eclipse

Step 1. Create a standalone maven project in Eclipse

Go to File -> New -> Other. On popup window under Maven select Maven Project. Then click on Next. Select the workspace location – either default or browse the location. Click on Next. Now in next window select the row as highlighted from the below list of archtypes and click on Next button.

maven-arctype-quickstart

Now enter the required fields (Group Id, Artifact Id) as shown below

Group Id : com.roytuts
Artifact Id : spring-faqs

Step 2. Modify the pom.xml file as shown below.

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>

    <groupId>com.roytuts</groupId>
    <artifactId>spring-faqs</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <packaging>jar</packaging>

    <name>spring-faqs</name>
    <url>http://maven.apache.org</url>

    <properties>
        <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
        <jdk.version>1.8</jdk.version>
        <junit.version>4.11</junit.version>
        <spring.version>4.1.5.RELEASE</spring.version>
    </properties>

    <dependencies>
        <!-- Spring framework -->
        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-core</artifactId>
            <version>${spring.version}</version>
        </dependency>

        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-context</artifactId>
            <version>${spring.version}</version>
        </dependency>

        <!-- junit -->
        <dependency>
            <groupId>junit</groupId>
            <artifactId>junit</artifactId>
            <version>${junit.version}</version>
            <scope>test</scope>
        </dependency>
    </dependencies>

    <build>
        <plugins>
            <plugin>
                <groupId>org.apache.maven.plugins</groupId>
                <artifactId>maven-compiler-plugin</artifactId>
                <configuration>
                    <source>${jdk.version}</source>
                    <target>${jdk.version}</target>
                </configuration>
            </plugin>
        </plugins>
    </build>

</project>

Step 3. If you see JRE System Library[J2SE-1.4] then change the version by below process

Do right-click on the project and go to Build -> Configure build path, under Libraries tab click on JRE System Library[J2SE-1.4], click on Edit button and select the appropriate jdk 1.8 from the next window. Click on Finish then Ok.

Step 4. Create src/main/resources folder for putting the resource files.

Do right-click on the project and go New -> Source Folder. Give Folder name: as src/main/resources and click on Finish button.

Step 5. Create an XML properties file under src/main/resources.

Do right-click on src/main/resources in the project and go New -> file. Give File name: as applicationContext.xml and click on Finish button.

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans.xsd">

    <bean id="springCollection" class="com.roytuts.spring.collection.SpringCollection">
        <property name="set">
            <set>
                <value>just some string</value>
                <value>another some string</value>
                <value>more value string</value>
            </set>
        </property>
    </bean>

</beans>

Step 6. Create a POJO class that contains list element

package com.roytuts.spring.collection;

import java.util.Map;

public class SpringCollection {

    private Set<String> set;

    public Set<String> getSet() {
        return set;
    }

    public void setSet(Set<String> set) {
        this.set = set;
    }

}

Step 7. Create a Test class which will test our code how it works

package com.roytuts.spring.collection;

import java.util.Set;

import org.junit.Before;
import org.junit.Test;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;

public class SpringCollectionTest {

    private SpringCollection springCollection;

    @Before
    public void setUp() {
        ApplicationContext applicationContext = new ClassPathXmlApplicationContext(
                "applicationContext.xml");
        springCollection = applicationContext.getBean("springCollection",
                SpringCollection.class);
    }

    @Test
    public void displaySet() {
        Set<String> set = springCollection.getSet();
        for (String string : set) {
            System.out.println(string);
        }
    }

}

Step 8. Run the above test class, you will get below output

just some string
another some string
more value string

That’s all. Thanks for reading.

Collection element set in Spring
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